(2x-4)/(x^2-2x)

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Solution for (2x-4)/(x^2-2x) equation: 


D( x )

x^2-(2*x) = 0

x^2-(2*x) = 0

x^2-(2*x) = 0

x^2-2*x = 0

x^2-2*x = 0

DELTA = (-2)^2-(0*1*4)

DELTA = 4

DELTA > 0

x = (4^(1/2)+2)/(1*2) or x = (2-4^(1/2))/(1*2)

x = 2 or x = 0

x in (-oo:0) U (0:2) U (2:+oo)

(2*x-4)/(x^2-(2*x)) = 0

(2*x-4)/(x^2-2*x) = 0

x^2-2*x = 0

x*(x-2) = 0

x-2 = 0 // + 2

x = 2

x*(x-2) = 0

(2*x-4)/(x*(x-2)) = 0

2*x-4 = 0 // + 4

2*x = 4 // : 2

x = 4/2

x = 2

x in { 2} 

x belongs to the empty set

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